The** magnetic flux **across the **loop** in the figure below, with a = 30 cm, is -30bB. How many magnetic lines of force are present in a specific area is determined by the magnetic flux.

For instance, the **magnetic flux** density is lower if fewer magnetic lines cover a large region of **cross section**. Knowing the magnetic flux also enables us to make an educated guess about the **magnitude** of the magnetic field in a particular area. The magnetic flux through a surface in **electromagnetism**, a branch of physics, is the surface integral of the normal component of the magnetic field (B) travelling through that surface. represented by A or B.

= ABcos(theta), = baBcos(theta), and = -30bB

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a downward force of 400 N is applied to the small piston with a diameter of 6 cm in the hudraulic lift system. What is the

a) upward force exerted by the large piston with diameter of 30 cm

b) if the input force pushes the small piston down by 25 cm how high will the large piston rise

**Pressure** will be constant at both ends, with the use of formula, the upward **force** is 10,000 N and the **height **is 625 cm

Pressure can simply be defined as a ratio of **force** to **area**. Hydraulic lift system makes use of pressure principles.

Given that a downward force of 400 N is applied to the small piston with a diameter of 6 cm in the hydraulic lift system.

What is the

a) upward force exerted by the large piston with diameter of 30 cm

**Pressure** will be the same at both end.

Since pressure P = F/A

The **area** of the piston = πr²

F1/A1 = F2/A2

Since π will cancel out, substitute the **Force** and **radius** r directly

400/0.06² = F/0.3²

F = 111111.1 × 0.09

F = 9999.99 N

F = 10,000 N

b) if the input force pushes the small piston down by 25 cm, we can know how **height** will the large piston rise by using the same formula

400/0.25 = 10000/L

1600 = 10000/L

L = 10000/1600

L = 6.25 m

L = 625 cm

Therefore, the upward **force** exerted by the large piston is 10,000 N approximately and the **height** is 625 cm

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1. a. Find the angle between a diagonal of a cube and one of its edges. Show all working. b. Is the line through (4,6,3) and (2,0, -1) parallel to the line through (6,22,12) and (1,7,2)? Your explanation must include full details. c. Two forces F1 and F2 with magnitudes 100 Newtons and 120 Newtons, respectively, act on an object at point P as shown in the figure (not to scale).

a. The angle between a diagonal of a cube and one of its edges is approximately 54.7356°.

b. No, the line through (4,6,3) and (2,0, -1) is not parallel to the line through (6,22,12) and (1,7,2).

C. question is incomplete.

a. To show the working, consider the diagonal of a** cube **with edge length "a":

**Diagonal **= √(a^2 + a^2 + a^2) = √(3a^2) = a√3

The length of the edge is "a".

To find the angle between the two, use the dot product formula:

cos(θ) = (a * a) / (a * √(3a^2)) = a / √(3a^2) = a / (a√3) = 1 / √3

Therefore, θ = cos^-1 (1 / √3) = 54.7356°

b. The line through (4,6,3) and (2,0, -1) is not **parallel **to the line through (6,22,12) and (1,7,2).

**Parallel lines** have the same direction and therefore the same slope. To check for parallelism, we can find the direction ratios of the lines.

The **direction ratio** of the line through (4,6,3) and (2,0, -1) is: (2-4,0-6,-1-3) = (-2,-6,-4)

The direction ratio of the line through (6,22,12) and (1,7,2) is: (1-6,7-22,2-12) = (-5,-15,-10)

Since the direction ratios are different, the two lines are not parallel.

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A body moving with uniform acceleration has a velocity of 14.2

when its a coordinate is 2.05. If its a coordinate 2.22 later is

-4.21, what is the x-component of its acceleration?

Answer in units of cm/s^2

**Answer:**

2.05 an $4.2 isn't the same result

**Explanation:**

no exceptions

draw the phasor for the emf e=(170v)cos((2π×60hz)t) at t=60ms.

The phasor **diagram** for the given **emf** has been drawn below and explained as well.

In electrical circuits, A phasor is a scaled line whose length represents an AC quantity that has both **magnitude** (peak amplitude) and direction (phase) frozen at some given time. It is generally represented by V=Vo sin(ωt+φ) where Vo represents the magnitude of the emf, ωt tells the phase at a given point in time and φ shows the initial stage.

In the given question-

(170V)cos((2π×60)t)

=(170V)sin(π/2-(2π×60)t)

ωt=2×π×60×60×10-³=7.2π

φ=π/2

Vo=170V

so, V at a given point will be,

V=170sin(π/2-7.2π)= -137.53 V

so, the **phasor** will look something like this(the image has been attached below).

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A particle with mass 2.30 g and charge +10.0μC enters through a small hole in a metal plate with a speed of 8.50 m/s8.50 m/s at an angle of 55.0∘. The uniform E→ field in the region above the plate has magnitude 6.50×10^3 N/C and is directed downward. The region above the metal plate is essentially a vacuum, so there is no air resistance. (a) Can you neglect the force of gravity when solving for the horizontal distance traveled by the particle? Why or why not? (b) How far will the particle travel, Δx, before it hits the metal plate?

No, the **force **of gravity cannot be neglected when solving for the horizontal distance traveled by the particle.

The gravitational force would be described as a force **of **attraction (attractive force) that attracts all physical forms having mass. It is by far the weakest recognized natural force. Mathematical representation. Mathematically, gravitational force can be represented as F = G m 1 m 2 r.

Earth's gravity comes from all its mass. All its mass makes a combined gravitational pull on all the **mass **in your body. That's what gives you weight.

And if you were on a planet with less mass than Earth, you would weigh less than you do here.

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Consider the circuit shown in (Figure 1). Assume E = 19 V.

A. What is the equivalent capacitance?

B. What is the charge on 3.0 μF capacitor?

C. What is the charge on 4.0 μF capacitor?

D. What is the charge on 6.0 μF capacitor?

The equivalent **capacitance** is 5.4μF, the charge on 3.0μF capacitor is 57μC, the charge on 4.0μF capacitor is 76μC, the **charge** on 6.0μF capacitor is 114μC.

Given from the diagram below the **emf** E = 19V

The **capacitance** of first capacitor (C1) = 3.0μF

The capacitance of second capacitor (C2) = 4.0μF

The capacitance of third capacitor (C3) = 6.0μF

We can see that the capacitors C2 and C3 are connected in **series** and C1 is connected in **parallel** to C2 and C3.

So, the capacitance in series is 1/C' = 1/4 + 1/6

C' = 2.4μF and Ceq = C' + C1 = 2.4 + 3 = 5.4μF

(a) The **equivalent** capacitance = 5.4μF

We know that E = Q/C where Q is the charge and E is the voltage.

(b) the charge on 3.0μF capacitor (Q1) = 19 x 3 = 57μC

(c) the charge on 4.0 μF capacitor (Q2) = 19 x 4 = 76μC

(d) the charge on 6.0 μF capacitor (Q3) = 19 x 6 = 114μC

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fig. 1 shows a motion di- agram of a car traveling down a street. the camera took one frame every 10 s. a distance scale is provided.

The graph obtain from the plot is **consistent **and the velocity is changing at different instance from the **distance** scale provided.

(a) In first frame to third frame car **velocity is decreasing **and in fourth frame car moves with constant velocity up to sixth frame. From seventh frame to ninth frame velocity is increasing

(b) Measure the x-value of the car at each dot and place your data in a table, showing each position and the instant of time at which it occurred.

The table below shows a **position and time** of a car traveling down a street.

t v

0 1200

1 1000

2 850

3 750

4 700

5 650

6 600

7 500

8 300

9 0

(c) Yes, **The slope** of position vs time graph gives velocity. We can explain from **graph** how the velocity is changing at different instance.

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The complete question is :

a) Describe what the car is doing in various regions.

(b) Note the position and time of the car at each dot and record in the table below.

Time t (s) Position x (m)

(c) Plot a graph of position vs. time below, labeling axes. Draw a curve of best fit through the points that passes through or close to as many of the data points as possible.

(d) Is your graph consistent with your description in part (a)? Explain.

state the law of conservation of energy

**Answer:**

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside.

**Explanation:**

I hope this quick explanation helps :D

**Explanation:**

Energy can neither be created or destroyed but can convert one form to the another

Why are there convection currents in the mantle?

Answer:

Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.

Convection currents are the result of differential heating. Lighter (less dense), warm material rises while heavier (more dense) cool material sinks. It is this movement that creates circulation patterns known as convection currents in the atmosphere, in water, and in the mantle of Earth.

Suppose a transparent vessel 30.0 cm long is placed in one arm of a Michelson interferometer, as in Example 25.2. The vessel initially contains air at 0 ° C and 1.00 atm. With light of vacuum wavelength 633 nm, the mirrors are arranged so that a bright spot appears at the center of the screen. As air is slowly pumped out of the vessel, one of the mirrors is gradually moved to keep the center region of the screen bright. The distance the mirror moves is measured to determine the value of the index of refraction of air, n. Assume that, outside of the vessel, the light travels through vacuum. Calculate the distance that the mirror would be moved as the container is emptied of air.

The distance that the mirror in **pressure **would be moved as the container is emptied of air is 0.0084 cm.

**What is pressure?**

**Pressure **is the amount of force applied to an area over a given **surface**. It is measured in units of force per area, such as pascals (Pa) or pounds per square inch (psi). Pressure is a fundamental physical property and is the result of the interaction of **forces** between particles of matter.

The index of refraction of air can be calculated using the **equation**:

n = c/v,

where n is the index of refraction, c is the speed of light in a vacuum, and v is the speed of light in the medium.

The speed of light in a vacuum is 3.00 x 10^8 m/s, and the speed of light in air is given by the equation:

v = c/n = (3.00 x 10^8 m/s)/(1.00028) = 2.99972 x 10^8 m/s.

Therefore, the index of **refraction **of air at 0 °C and 1.00 atm is 1.00028.

The difference between the index of refraction of air and the index of refraction of vacuum is 1.00028 – 1 = 0.00028.

Distance = (0.00028)*(30.0 cm) = 0.0084 cm

Therefore, the **distance **the mirror must be moved as the container is emptied of air is 0.0084 cm.

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how can you maximize the torque applied to a given lever arm without applying more force?

**Answer:**

Apply the force in the same direction, but at a distance further away from the pivot.

**Explanation:**

Consider a force of magnitude [tex]F[/tex] applied on to this lever.

Let [tex]r[/tex] denote the distance between the pivot and the point where this force is applied. Let [tex]\theta[/tex] denote the angle between the force and the lever.

The **torque** [tex]\tau[/tex] applied on this lever would be:

[tex]\tau = r\, F\, \sin(\theta)[/tex].

Assume that the magnitude and direction of the force stay the same, such that [tex]F[/tex] and [tex]\theta[/tex] would be constant. Note that torque [tex]\tau = r\, F\, \sin(\theta)[/tex] would be proportional to the distance [tex]r[/tex]. This distance can be increased by moving the force further away from the pivot.

Therefore, when the magnitude and direction of the external force on the lever are the same, applying the force at a point further away from the pivot would increase the torque.

Consider the circuit shown in (Figure 1) . Suppose that E = 11 V .

You may want to review (bookLink.gif pages 738 - 740) .

Part A

Find the current through the resistor a.

Express your answer to two significant figures and include the appropriate units.

Part B

Find the potential difference across the resistor a.

.Part C

Find the current through the resistor b.

Part D

Find the potential difference across the resistor b.

Part D

Find the potential difference across the resistor b.

Part E

Find the current through the resistor c.

Part F

Find the potential difference across the resistor c.

Part G

Find the current through the resistor d.

Part H

Find the potential difference across the resistor d.

The potential difference of a battery is 11V. Hence, the **current **through the resistor a is 1.1A.

Possibly existing variation between any two points The amount of labour required to move a unit positive charge along any path between two places in the electric field is defined as the distance that can be traveled by the charge without accelerating.

What are resistors used for?A two-terminal passive electrical component used in electrical circuits to limit or regulate the flow of current. A resistor's primary function is to lower the **voltage **and reduce current flow in a specific area of the circuit.

Effective resistance of b, c and d

1/R => 1/(5+5)+1/10

R= 5Ω

V = IR

I = V/R ;

I = 11/(5+5) => 1.1A

Part A => 1.1A

Part B => (5 x 1.1) = 5.5V

Part C => I/2 => 1.1/2 => 0.55A

Part D => (0.55 x 10) => 5.5V

Part E => 0.55A

Part F=> 0.55 x 5 => 1.25V

Part G => 0.55A

Part H => 0.55 x 5 = 1.25V

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Mitochondria have a "bag within a bag" structure. This structure is necessary in order to:

a) create a concentration gradient of certain molecules between the regions inside and outside the "inner bag," a form of potential energy.

b) keep molecules of ADP in close proximity to molecules of the ATP-synthesizing enzyme.

c) allow light-reactive accessory pigments to be embedded within the membranes.

d) segregate the most toxic digestive enzymes from molecules of ATP and NADP'.

e) None of the above.

Create a concentration gradient of certain **molecules** between the regions inside and outside the "inner bag," a form of potential energy.

**Potential energy** is the energy stored in an object due to its position or chemical composition. It is the energy of an object that is ready to be released and converted into kinetic energy. Examples of potential energy include the energy stored in a compressed spring, the energy stored in a raised weight, the energy stored in a charged battery, and the energy stored in the bonds of molecules or atoms.

The inner and outer membranes of the mitochondria form a "bag within a bag" structure, which is necessary to create a concentration gradient of certain molecules between the inner and outer regions. This gradient allows for the formation of a potential energy source. This potential energy is used to drive the synthesis of **ATP** from ADP and the enzyme responsible for this reaction. This structure also helps to keep molecules of ADP close to the enzyme, thus allowing for efficient synthesis of ATP. Additionally, this structure allows for the embedding of light-reactive accessory pigments within the membranes. This way, they can absorb the energy of incoming light and convert it into chemical energy, which can then be used to power the synthesis of ATP.

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A 2 kg object going 30 m/s feels a −4 N force for 8 seconds, find the object’s final velocity

When a 2 kg object going 30 m/s feels a −4 N **force **for 8 seconds, the** final velocity** of the object is **14 m/s.**

The rate at which a body's displacement changes in relation to time is known as its **velocity**. Velocity is a vector quantity with both magnitude and direction. SI unit of **velocity **is meter/second.

Initial **momentum **of the object = 2 kg× 30 m/s = 60 kg-m/s.

**Impulse **applied on the object = - 4 N×8 second = - 32 N-second.

Hence, **final momentum **of the object = (60 - 32) kg-m/s = 28 kg-m/s.

So, the **final velocity **of the object is= (28/2) m/s = 14 m/s

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Two objects of equal mass are placed 0.8meters apart. There is an attractive force between them of 6.253 x 10-10Newtons. What is the value of each mass?

**Answer: The value of each mass is approximately 9.8 x 10^-5 kg. ✅**

**Explanation:**

**PLEASEEEE GIVE BRANLIEST **

To solve for the mass of each object, we can use the formula F = G(m1m2)/r^2, where F is the force between the two objects, G is the gravitational constant (6.67 x 10^-11 N*(m^2)/(kg^2)), m1 and m2 are the masses of the two objects, and r is the distance between them.

Given that F = 6.253 x 10-10 N and r = 0.8 meters, we can plug these values into the formula and solve for m1 and m2 (which are equal in this case)

**6.253 x 10-10 N = (6.67 x 10^-11 N*(m^2)/(kg^2)) * (m1 * m2) / (0.8 m)^2**

**m1 = m2 = sqrt((6.253 x 10-10 N) * (0.8 m)^2 / (6.67 x 10^-11 N*(m^2)/(kg^2)))**

**m1 = m2 = sqrt((6.253 x 10-10 N) * (0.8^2 m^2) / (6.67 x 10^-11 N*(m^2)/(kg^2)))**

**m1 = m2 = sqrt((6.253 x 10-10 N) * (0.64 m^2) / (6.67 x 10^-11 N*(m^2)/(kg^2)))**

**m1 = m2 = sqrt((6.253 x 10-10 N) * (0.64 ) / (6.67 x 10^-11 N))**

**m1 = m2 = sqrt((6.253 x 10-10 N * (0.64 )) / (6.67 x 10^-11 N))**

**Answer:**

**Explanation:**

According to gravitation law of universe,

Force=(G*M1*M2)/R^2

R=8/2=4m ,F=6.253*10^-10

M^2/R^2=6.253*10^-10/6.6743*10^-11

M=12.243KG

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from an evolutionary perspective, the most basic division among all organisms on earth is among:

From an **evolutionary** standpoint, the division between bacteria, archaea, and eukarya is the most **fundamental** one among all living things on earth.

Since both Bacteria and Archaea are made up of **unicellular** **organisms**, scientists once believed that these two domains of life were the most closely linked to one another. The most closely linked domains, according to new genome sequencing data, are actually Archaea and Eukarya. Prokaryotic **cells** lack membrane-bound cell organelles such mitochondria, the Golgi apparatus, and chloroplasts, among other traits. There isn't a tightly confined, clearly defined **nucleus**. Circular DNA makes up genetic material, which is found bare in the cytoplasm of cells.

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Which of the graphs illustrate how the current through an inductor might possibly change over time?(Figure 1) Type the numbers corresponding to the right answers in alphabetical order. Do not use commas. For instance, if you think that only graphs C and D are correct, type CD. Graph A Current (MA) 3.5 3 2.5 2 1.5 1 0.5 0

Time (ms) 0 0.5 1 1.5 2 Graph B Current (MA) 3.5 3 2.5 2 1.5 0.5 0 Time (ms) 0 0.5 1 1.5 2 Graph C Current (MA) 3.5 3 2.5 2 1.5 1 0.5 0

Time (ms) 0 0.5 1 1.5 2

Graph D Current (MA) 3.5 3 2.5 2 1.5 1 0.5 0

Time (ms) 0 0.5 1 1.5 2

**Induction** describes the fundamental action of creating currents with magnetic **fields**.

To distinguish it from charging by induction, which makes use of the **electrostatic** Coulomb force, this method is sometimes known as magnetic induction. Faraday reasoned that there must be an electromotive force moving the charges through the coil if a **current** is created in the coil. This interpretation was found to be wrong; instead, the energy added to the charges in the coil comes from an outside source that moves the magnet. The electromotive force is actually a potential since the energy added per unit **charge** is measured in volts. Regrettably, the term electromotive force stuck, along with the possibility for people to mistake it for a genuine force.

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Diffraction Limit:

a) How far away can a human eye distinguish two car headlights 2.0m apart? Consider only diffraction effects and assume an eye pupil diameter of 6 mm and a wavelength of 560 nm.

b) What is the minimum angular separation an eye could resolve when viewing two stars, considering only diffraction effects?

c) In reality, the minimum angular separation is about 1′ of arc. Why is it not equal to your answer in part b)?

The human eye can distinguish two car headlights 2.0m apart when the **angular separation** is about 0.03°.

**Diffraction** is the bending of waves around an obstacle or through an opening. When light or sound **waves** encounter an obstacle, the waves are scattered and spread out in a pattern known as a diffraction pattern. The size and shape of the obstacle affects the amount of diffraction that occurs. The same is true for an opening, such as a slit or a hole, which causes the waves to spread out in multiple directions. Diffraction is an important concept in many areas of physics, such as optics, acoustics, and quantum mechanics.

This is calculated by using the formula θ = 1.22λ/D, where θ is the angular resolution, λ is the wavelength of the light, and D is the diameter of the eye pupil. Assuming a light wavelength of 560nm and an eye pupil diameter of 6mm, the angular resolution is 0.03°.

The minimum angular separation an eye could resolve when viewing two stars, considering only diffraction effects, is 0.0003°. This is calculated using the same formula as before, only with the wavelength set to 550nm.

In reality, the minimum angular separation is about 1′ of arc, which is significantly larger than the answer calculated in part b). This is because diffraction effects are the only factor taken into account in part b), while in reality, other factors such as the eye's optical aberrations, the eye's accommodation, and atmospheric turbulence all play a role in limiting the resolution of the eye. Additionally, the eye's acuity is not constant and can be affected by fatigue and other factors. Thus, the true angular resolution of the eye is much lower than the theoretical limit calculated in part b).

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The maximum height of a cylindrical column is limited by the compressive strength of the material; if the compressive stress at the bottom were to exceed the compressive strength of the material, the column would be crushed under its own weight. Part 1 out of 3

(a) For a cylindrical column of height h and radius r, made of material of density rho, calculate the compressive stress at the bottom of the column. compressive stress =

A **cylindrical** column has height h and radius r, made of material of density ρ. The** compressive** **stress **at the bottom of this column is ρgh.

A cylinder's **volume** refers to the amount of interior space it has to hold a given quantity of material. And, this is given by [tex]V = \pi r^2h[/tex] where h is the cylinder's height and r is the cylinder's radius.

Given the cylinder's radius is r, height is h, and density is ρ. Then, the **mass **of the cylinder is calculated by multiplying the cylinder's volume and density. This is written as [tex]M = \pi r^2h\times \rho[/tex].

And the cylinder's **weight** is calculated by multiplying mass and gravity g. This is written as [tex]W = \rho \pi hr^2\times g[/tex].

We have to calculate the compressive stress at the bottom of the column. So the area of the bottom circle [tex]A = \pi r^2[/tex]. The **compressive **stress be then calculated as follows,

[tex]\begin{aligned}\text{Compressive stress}&=\frac{\text{ Weight}}{\text{Area}}\\&= \frac{(\rho \pi hr^2g)}{(\pi r^2)}\\&= \rho gh \end{aligned}[/tex]

The required **answer** is ρgh.

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write the formula for isothermal compressibility (see example 5) in terms of p

Isothermal compressibility is given by** K=−1V(∂V∂P)T.**

**What is meant by isothermal compressibility?**

Isothermal compressibility is defined by the fractional differential change in volume due to a change in pressure.

**What is the isothermal process?**

An isothermal process is a thermodynamic process in which the temperature of a system remains constant. The transfer of heat into or out of the system happens so slowly that thermal equilibrium is maintained.

**How is isothermal compressibility calculated?**

To measure isothermal compressibility a known increment of pressure must be applied and the consequent isothermal volume change measured. During compression, however, heat is generated in the test liquid and must be dissipated before the volume change can be measured.

**Is isothermal positive or negative?**

The isothermal compression of the gas was performed in two ways, one irreversible and one reversible. The work done on the gas is positive because the gas is compressed; the surroundings do positive work on the gas.

Thus, the formula is ** K=−1V(∂V∂P)T.**

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an object slides off a table 10 meters above the ground with an initial horizontal speed of 5 meters per second as shown above. Calculate the time between the objects leaving the table and hitting the ground

The **time **that have been taken for the ball to fall to the **ground **is 2 s.

We have to note that in this case, what we are trying to find is the time that have been taken. The question says that an object slides off a table 10 meters above the ground with an **initial **horizontal speed of 5 meters per second.

Now;

**Distance **that have been covered = 10 meters

Speed with which the ball falls = 5 meters per second

Speed = distance/Time

Time = Distance/Speed

Time = 10 m/5 m/s

Time = 2 s

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if the current at t=0 is 12.0a, what is the current at t=2.00s?

When the **current** is I, the energy is stored as U B.= 2 1 LI 2, where L denotes the self-**inductance**.

The pace of **development** of this is dt dU \sB

="Li dt di"

where I is determined by the **equation** i= R E (1e t/ L.) (increase of current), and the derivative of that equation (or the use of Eq. C =RC) yields di/dt. As a result, at time t=1.61 using the symbols V to represent the battery voltage (12.0 volts) and R to represent the **resistance** (20.0), we have L.

dt dU \sB\s = \sR \sV \s2 \s (1−e \s−t/τ \sL)e \s−t/τ \sL

= \s20.0Ω \s(12.0V) (12.0V) 2 \s (1−e \s−1.61 \s )e \s−1.61 \s

=1.15W

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A manufacturing company has a machine that can hold a maximum volume of 300 cm3 of liquid silver. This volume of liquid silver has a mass of approximately 2.8 kg. The company has a second machine that can only hold a maximum volume of 150 cm3 of liquid silver. What is the approximate mass of liquid silver that the second machine can hold?

**Approximately **1.4 kg mass of liquid silver that the second machine can hold.

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Before a collision, a 25 kg object is moving at 12 m/s to the right. After a collision with stationary box, the 25 kg object moves at 8 m/s to the right. What is the resulting momentum of the box?

The initial momentum of the 25 kg object is 25 kg * 12 m/s = 300 kgm/s. After the collision, the momentum of the 25 kg object is 25 kg * 8 m/s = 200 kgm/s. According to the conservation of momentum, the momentum lost by the 25 kg object is equal to the momentum gained by the box. Therefore, the resulting momentum of the box is 300 kgm/s - 200 kgm/s = 100 kg*m/s.

The symbol used for a magnetic pole is:

m

M

P

p

The symbol used for a **magnetic pole **is option Ana d B: "m" and "M" , which are used to indicate North and **South magnetic poles.**

In **physics**, a magnetic pole is a point on a magnet where the magnetic field is most concentrated. The north pole of a magnet is the pole that points towards the **Earth's geographic** north pole, while the south pole of a magnet is the pole that points towards the Earth's geographic south pole.

Therefore, These **poles **are labeled "N" (for north) and "S" (for south) respectively, but it's also common to use the symbols "m" and "M" to indicate magnetic poles.

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A ball of mass 0.10 kg is dropped from a height of 18 m. Its momentum when it strikes the ground is? (2.4 kg m/s, 1.9 kg m/s, 1.5 kg m/s, 3.8 kg m/s).

A ball of **mass **0.10 kg is dropped from a height of 18 m.**1.5 Kgm/sec** is strikes the ground. option (**c**) is correct.

**What is mass ?**

**Mass**, pronounced "măs," is a unit of measurement for the quantity of substance that comprises a **physical **body. In classical mechanics, an **object's **mass is important because it affects the amount of inertia it possesses and the **force **required to accelerate it according to **Newton's **equations of **motion**.

What is **momentum **?

The mathematical relationship between **mass **and **velocity **is that of **momentum**. The amount of motion that is made up of the mass moved and the **speed **at which it is moving is known as **momentum**.

Momentum = sqrt (2mK) [K = Kinetic energy of block]

Applying energy conservation

K when it hits ground = mgh

So P = sqrt ( 2m2 gh) = m sqrt (2gh) = 0.10 * sqrt(2*9.8*12) = 1.534 Kgm/sec

So correct option is C) 1.5 Kgm/sec

Therefore, A ball of **mass **0.10 kg is dropped from a height of 18 m.**1.5 Kgm/sec** is strikes the ground. option (**c**) is correct.

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Thursday Homework 1-12-23 SHOW ALL YOUR WORK! 5. A swimming pool is 8 meters long, 6 meters wide, and 2 meters deep. The water- resistant paint needed for the pool costs $6 per square meter. How much will it cost to paint the pool? a. How many faces of the pool do you have to paint? b. How much paint (in square meters) do you need to paint the pool? c. How much will it cost to paint the pool? Who can help me ?

Since you aren't painting on top of the pool, you are painting the pool's four sides, its bottom, and its five faces. 104 square meters is the **surface area.** The total cost of the paint was $624.

A three-dimensional shape's surface area is the **sum **of all of its faces. Finding the area for every face and adding them together gives us the land area of a shape.

The water-resistant paint required for the pool, which is 8 meters long, 6 meters wide, and 2 meters deep, costs $6 per sq meter.

A) Because you aren't painting on top of the pool, you are painting the pool's four sides, its bottom, and its five faces.

B) The pool requires 104 square meters of paint.

Just use surface area equation assuming the pools is a **rectangular** prism:

SA = wl + 2(hl) + 2(hw)

Since we're only including pool's bottom, don't add times 2 for wl.

l = 8 m

w = 6 m

h = 2 m

SA = (6)(8) + 2((2)(8)) + 2((2)(6))

SA = 104 sq m

C) The total cost of the paint was $624. $624 is equivalent to $104 × 6 square meters.

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The Lyman series of emission lines of the hydrogen atoms are those for which nf = 1. a) determine the region of the electromagnetic spectrum in which the lines of the Lyman series are observed. b) Calculate the wavelengths of the first three lines in the Lyman series-those for which ni = 2,3,and 4. Please show all work

The** **Lyman series of emission lines of **hydrogen** atoms are observed in the ultraviolet region and the wavelengths of the first three lines are -822.5 nm, -364.6 nm and -182.3 nm.

a) The region of the electromagnetic spectrum in which the lines of the Lyman series are observed is the **ultraviolet** region.

The lines of the Lyman series are observed in the ultraviolet region because the energy levels involved in these transitions are located in the UV portion of the spectrum.

The series starts from the first excited state and ends with the ground state, each transition corresponds to a specific wavelength of UV light.

b) The wavelengths of the first three lines in the **Lyman series** can be calculated using Rydberg formula and specific values of [tex]n_{i[/tex] and [tex]n_{f}[/tex] :

λ = R(1 ÷ [tex]n_{i[/tex]² - 1 ÷[tex]n_{f}[/tex]²)

where λ is the wavelength, R is the **Rydberg** constant (approximately 1.097 x 10⁷ m⁻¹), [tex]n_{i[/tex] is the initial energy level, and [tex]n_{f}[/tex] is the final energy level.

For the first line ([tex]n_{i[/tex] = 2, [tex]n_{f}[/tex] = 1):

λ = 1.097 x 10⁷ m⁻¹ (1÷2² - 1÷1²) = 1.097 x 10⁷ m⁻¹ (1÷4 - 1) = 1.097 x 10⁷ m⁻¹ (-3÷4) = -822.5 nm.

For the second line ([tex]n_{i[/tex] = 3, [tex]n_{f}[/tex] = 1):

λ = 1.097 x 10⁷ m⁻¹ (1÷3² - 1÷1²) = 1.097 x 10⁷ m⁻¹ (1÷9 - 1) = 1.097 x 10⁷ m⁻¹ (-8÷9) = -364.6 nm.

For the third line ([tex]n_{i[/tex] = 4, [tex]n_{f}[/tex] = 1):

λ = 1.097 x 10⁷m⁻¹ (1÷4² - 1÷1²) = 1.097 x 10⁷ m⁻¹ (1÷16 - 1) = 1.097 x 10⁷ m⁻¹ (-15÷16) = -182.3 nm

Because it is in the ultraviolet portion of the electromagnetic spectrum, take note that the **wavelength** is negative.

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Consider a fusion reaction in which a proton fuses with a neutron to form a deuterium nucleus. How much energy is released in this reaction?(The mass of the deuterium nucleus is 2.01355u). Answer in Me

The difference in **mass **is then 2.01649u - 2.01355u = 0.00294u. This means that the energy released in this reaction is equal to 0.00294u × (c^2) = 4.621 x 10^-12 J.

**What is mass?Mass **is a measure of the amount of matter an object contains. It is different from weight, which is a measure of the

The **energy **released in this reaction is equal to the mass difference between the products and the reactants multiplied by the speed of light squared. In this reaction, the mass of the **reactants **(1 proton and 1 neutron) is equal to 1.007825u + 1.008665u = 2.01649u.

The **mass **of the product (deuterium nucleus) is 2.01355u.

This means that the energy released in this reaction is equal to 0.00294u × (c^2) = 4.621 x 10^-12 J.

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Which is more easily diffracted around the buildings AM or FM radio waves? Why?

FM radio waves are more easily diffracted around buildings than AM radio waves because they have lower frequencies and longer **wavelengths**.

**What is wavelength?**

Wavelength is the distance between two **successive** crests of a wave. It is the distance that a wave travels in one complete cycle, and is measured in **meters **or other units of length.

**FM waves** are able to bend around obstacles more easily than AM waves due to their longer **wavelength**. The longer wavelength of an FM wave allows it to bend and diffract around obstacles more easily than the shorter wavelength of an AM wave, which is more likely to be blocked or reflected by **obstacles**.

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How is the introductory statement related to the thesis statement?they are not related to each other at allthe introductory statement is the outline for the thesis statementthe introductory statement announces the topic and sets the context for the thesis statementthey are two names for the same thing
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