Part A

Determine the number of protons, neutrons, and electrons.

Please explain

An isotope of potassium with the same number of **neutrons **as argon-40 has 19 **protons**, 21 neutrons, and 19 electrons. Potassium has an atomic number of 19, meaning it normally has 19 protons and 19 electrons.

However, this **isotope **has the same number of neutrons as argon-40, which has an atomic number of 18 and a mass number of 40. This means that argon-40 has 18 **protons **and 22 neutrons. Since the isotope of potassium has the same number of neutrons, it must also have 18 protons, but to maintain a neutral charge, it must also have 19 electrons. Thus, the isotope of **potassium **with the same number of neutrons as argon-40 has 19 protons, 21 **neutrons**, and 19 electrons.

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When operating an aircraft at cabin pressure altitudes above 12,500 feet msl up to and including 14,000 feet msl, supplemental oxygen shall be used during?

Supplemental oxygen shall be used in that flight time in **excess of 30 minutes** at those altitudes.

Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of **oxygen **inside the blood by approximately 4 percentage points, researchers say.

The higher the altitude, the less oxygen there is in the air and the lower the overall **air pressure** is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.

The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of **14,000 feet MSL.**

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1. A 500 g piece of silver at 250°C is submerged in 1000 g of water at 5°C to be cooled. Determine the

final temperature of the silver and water. Given Cwater = 4180 J/kg°C and Csilver = 240 J/kg°C.

Taking into account the definition of calorimetry, the **final temperature **of the silver and water is **11.84 °C**.

Calorimetry is the **measurement and calculation of the amounts of heat **exchanged by a body or a system.

**Sensible heat** is defined as the amount of heat that a body absorbs or releases **without any changes in its physical state** (phase change).

So, the **equation **that allows to calculate heat exchanges is:

**Q = c× m× ΔT**

where:

Q is the heat exchanged by a body of mass m. c is the specific heat substance. ΔT is the temperature variation.Final temperature of the silver and waterIn this case, **you know**:

**Replacing** in the expression to calculate heat exchanges:

For silver: Qsilver= 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature of silver - 250 C)

For water: Qwater= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature of water - 5 C)

If two isolated bodies or systems exchange energy in the form of heat, the **quantity received by one** of them is **equal to the quantity transferred by the other body**. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the silver gives up will be equal to the heat that the water receives. Therefore:

**- Qsilver = + Qwater**

And the final temperature of the silver is equal to the temperature of the water (Final temperature of silver= Final temperature of water= Final temperature). Then:

- 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature - 250 C)= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature - 5 C)

Solving:

- 120 [tex]\frac{J}{C}[/tex]× (Final temperature - 250 C)= 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]× (250 C - Final temperature) = 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]×250 C - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 4180 [tex]\frac{J}{C}[/tex]×5 C

30,000 J - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 20,900 J

50,900 J= 4300 [tex]\frac{J}{C}[/tex]×Final temperature

50,900 J÷ 4300 [tex]\frac{J}{C}[/tex]= Final temperature

*11.84 °C= Final temperature*

Finally, the **final temperature **of the silver and water is **11.84 °C**.

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what is kinematics ?

explain ~

[tex] \\ \\ [/tex]

tysm! :)

**Answer:**

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. The study is often referred to as the geometry of motion, and it models these motions mathematically using algebra

**Answer:**

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion is kinematics

A 15.2 kg mass has a gravitational potential energy of -342 J. How high from the ground is it? Group of answer choices GPE cannot be negative 2.3 m 22.5 m 530 m

**A**. The **height **above the ground reached by the mass is **2.3 m.**

P.E = mgh

where;

m is mass h is height reached by the objectg is acceleration due to gravityh = P.E/mg

h = (342)/(15.2 x 9.8)

h = 2.3 m

Thus, the **height **above the ground reached by the mass is **2.3 m.**

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________ occurs when a person is holding an object that is directly hit or splashed by lightning.

**Contact injury** happens when a person is holding an object that is directly hit or splashed by lightning.

To find answer, we need to know more about the** lightning and injuries.**

Thus, we can conclude that,** contact injury** occurs when a person is holding an object that is directly hit or splashed by lightning.

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When someone is holding something that has been struck or splashed by lightning, **contact damage** occurs.

We need additional information concerning** lightning and injuries** in order to identify the solution.

In light of this, we can say that **contact injuries** happen when a person is holding an object that has been struck by lightning or splashed by it.

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A fireworks shell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m. How long did the acceleration last

The **acceleration** lasted for **0.007s**.

To find the answer, we need to know about the **Newton's equation of motion**.

Newton's equations are

V= final velocity, U= initial velocity, a= acceleration, t= time and S = distance

What's the acceleration, if the fireshell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m?Here, U= 0m/s, V= 60.0 m/s, S= 0.200 m60²-0= 2a×0.2= 0.4a

Thus, we can conclude that the **acceleration of** **the fireshell** lasted for **0.007s**.

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A mountain skier has begun descending the 30o slope. if the coefficient of kinetic friction is 0.10, what is her acceleration?

The **acceleration **of the body is found to be **-4.05 m/s^2**

We define the **acceleration **as the rate of **change of the velocity** with **time**. Hence, we can write that;

a = (μcosθ - sinθ)g

a = acceleration

μ = coefficient of kinetic friction

θ = angle of inclination

g = acceleration due to gravity

Thus;

a = (0.10cos 30 - sin 30) 9.8

a = **-4.05 m/s^2**

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Although centuries ago, astronomers thought that a nova was a new star, appearing for the first time in the heavens, today we know that it is:

**Astronomers **thought that a nova was a new star, appearing for the first time in the **heavens**, today we know that it is as a binary star **system**.

A **binary **star system is known to be one where one star is known to be called a white **dwarf **and there is a mass that is said to be transferred to it

A **binary **star is known to be a kind of a system that is composed of two stars that are known to be gravitationally held together to and in orbit near **each **other.

Note that Binary stars in the night sky are ones that are often seen as a single object and thus **Astronomers **thought that a nova was a new star, appearing for the first time in the **heavens**, today we know that it is as a binary star **system**.

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An engine has an input of heat energy of 10,750 J and does 2,420 J of work. Which of the following is the heat loss?

Group of answer choices

a. 13,200 J

b. 8,330 J

c. 4.44 J

c. 0.225 J

**B. ** The **heat loss** by the heat engine is **8,330 J.**

The **heat loss** by the heat engine is calculated as follows;

H = E - W

where;

H is heat lossE is input energyW is work doneH = 10,750 J - 2,420 J

H = 8,330 J

Thus, the **heat loss** by the heat engine is **8,330 J.**

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in the photoelectric effect a photon with an energy of 5.3 * 10^-19 J strikes an electron in a metal

The **velocity** of the photo electron is **6.11 × 105 ms**

**Given :**

Supplied energy, Es = 5.3 x 10-19 J

Minimum energy of the electron to escape from the metal, E. = 3.6 x 10-19 J

**To Find :**

Velocity of photoelectron

**Solution :** The energy supplied by the photon is equal to the sum of **minimum escape energy** and the kinetic energy of the escaping electron. So

5.3 × 10^-19 J = 3.6 × 10^-19 J + K

K = 5.3 x 10^-19 - 3.6 x 10^-19

K = 1.7 × 10^-19 J

The formula of **kinetic energy** is given by:

K = 1/2 mv^2

v = √2K/m

= √2 x 1.7 x 10^-19

√ 9.1 x 10^-31

v = 6.11 x 10^5 m/s

**So, the velocity of the photo electron is 6.11 x 10^5 m/s **

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A convex lens of focal length 25 cm is in contact with a concave lens of focal length 50 cm. The equivalent focal length of this combination-lenses should be Group of answer choices

The equivalent **focal length** of this **combination-lenses** should be +50 cm.

**Given:**

Focal length of convex lens, f₁ = +25 cm

Focal length of concave lens, f₂ = -50 cm

**Calculation:**

We know that the **power of a lens** is given as:

P = 1 / f

where, f is the focal length of lens

Now, the power of convex lens can be calculated as:

P₁ = 1/f₁

= 1/(25×10⁻² m)

= 100/25

= +4 D

Similarly, the power of concave lens can be calculated as:

P₂ = 1/f₂

= (1/-50×10⁻² m)

= -100/50

= -2 D

Thus, the power of the combined lenses can be calculated as:

P₍₁₊₂₎ = P₁ + P₂

= +4 D - 2 D

= +2 D

Now, the combined focal length of the lens can be calculated as:

f₍₁₊₂₎ = 1 / P₍₁₊₂₎

= 100 / 2 D

= +50 cm

Therefore, the **equivalent focal length** of this combination-lenses will be **+50 cm.**

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How much power will be required to force a current of 4.13 amps to flow through a conductor whose resistance is 113 ohms? Use two decimals for your answer. Round your answer to two decimals.

The **power required** to force the current of 4.13 A to flow through the conductor is **1927.43 watts**

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = square current (I²)× resistancet (R)

**P = I²R**

P = I²R

P = 4.13² × 113

**P = ****1****9****2****7****.****4****3**** ****watts**

Thus, the **power required **is **1927.43 watts**

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Rank in order, from largest to smallest, the magnitudes of the momentum p1x through p5x of the objects presented in (Figure 1). Rank the magnitudes of the momentum from largest to smallest. To rank items as equivalent, overlap them.

The decreasing order of the **momenta** are b>a=d=e>c.

Solution: The **momentum** of all the options are mentioned below according to the formula:

a. p = 20 × 1 = 20gm/s

b. p = 20 × 2 = 40gm/s

c. p =10 × 1 = 10gm/s

d. p = 10 × 2 = 20 gm/s

e. p =200 × 0.1 = 20gm/s

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Question:

I hope you are trying to ask the question below:

Rank in order, from largest to smallest, the **momenta** a to e of the objects

a. 20 g & 1 m/s

b. 20 g & 2 m/s

c. 10 g & 1 m/s

d. 10 g & 2 m/s

e. 200 g & 0.1 m/s

a pulley is assumed massless and frictionless and rotates freely about its axle. the blocks have masses m1=40g and a block m2= 20g, and block m1 is pulled to the right by a horizontal force magnitude f=0.03n. find the magnitude of acceleration of a block m2 and the tension in the cord.....?

The magnitude of** acceleration** of a **block m₂** is 0.05 m/s² and the **tension** **in the cord** is 0.01 N.

**Given:**

mass of block 1, m₁ = 40 gm = 40×10⁻³ kg

mass of block 2, m₂ = 20 gm = 20×10⁻³ kg

Applied force, F = 0.03 N

**Calculation:**

Consider the** **free-body diagram of the system as shown below. Using **Newton's second law** of motion we get:

F = ma

where F is the applied force

m is the total mass of the system

a is the acceleration of block 2 (as it is pulled by horizontal force)

From the above equation we get:

0.03 N = (m₁+m₂) a

⇒ a = (0.03 N) / (m₁+m₂)

⇒ a = (0.03 N) / (40×10⁻³ kg + 20×10⁻³ kg)

⇒ a = 0.5 m/s²

Now, from the free-body diagram of block 2 as shown in figure 3, we get:

Balancing the forces along the **horizontal**:

∑Fₓ = 0

∴ T = m₂ a

where T is tension in the string

a is the acceleration of block 2

Applying values in the above equation we get:

T = (20×10⁻³ kg) × (0.5 m/s²)

= 0.01 N

Therefore, the acceleration of block 2 due to the applied** horizontal force **is 0.5 m/s² and the **tension **in the cord is 0.01 N.

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A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.

The **diameter **of the largest orbit just before the protons exit the **cyclotron** is 39 cm.

The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

**The kinetic energy for the protons can be computed by using the formula:**

mv² = 2 K.E

v = sqrt( 2*KE / M)

the kinetic energy of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

**v = 3.53 × 10⁷ m/s**

The radius of the orbit can be estimated by using the formula:

**mv² / R = qvB**

r = q*v / mv²

r = ( 1.67* 10^-27 *** **3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

**r = 0.19415 m**

Since diameter (D) = 2r,

D= 2(0.19415 m)

D= 0.39 m

D≅ 39 cm

The time period to **complete a revolution** around the **spiral trajectory** is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

**T = 0.7 × 10⁻⁷ s**

Finally, the** number of orbits** that the proton does to **complete the revolution** in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71

**n ≅ 14000 revolutions**

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

A person stands on the ground with a slingshot and tries to hit a high limb on a nearby tree. The limb is 18.3 feet above the ground. What is the minimum initial velocity in meters/second of a rock leaving the slingshot at 6 feet above the ground that would be able to reach the limb

The minimum **initial velocity** of the rock is V = 8.56 m/sec.

According to the rule of **conservation of energy**, energy can only be transformed from one form of energy to another and cannot be created or destroyed. This indicates that unless energy is added from the outside, a system always has the same quantity of energy.

Calculate the rock's minimal **initial velocity** in meters/second as it exits the slingshot at a distance of 6 feet [tex]$\left(h_{2}=6\right.ft.)[/tex] above the ground.

Using the provided information, the net height of the limb is calculated as shown below.

[tex]$$h &=h_{1}-h_{2}$$[/tex]

h = 18.3 - 6

h = 12.3

Now, using the **conservation of energy** the minimum initial velocity of the rock is computed as shown below,

**Kinetic energy of the rock = Potential energy the rock**

[tex]$$\begin{aligned}\frac{1}{2} m V^{2} &=m g h \\\frac{1}{2} V^{2} &=g h \\\frac{1}{2} V^{2} &=\left(32.1 \mathrm{ft} / \mathrm{s}^{2}\right)(12.3 \text { feet }) \\V &=\sqrt{2\left(32.1 \mathrm{ft} / \mathrm{s}^{2}\right)(12.3 \mathrm{feet})}\end{aligned}$$[/tex]

V = 28.10 [tex]\frac{ft}{s}[/tex].

The minimal **initial velocity** in meter/second is 8.56.

Therefore, the minimum initial velocity of the rock is 8.56 m/sec

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John is talking to his friend about painting a fence. He states that if he uses a roller brush he will cover the fence faster than if he uses a bristle brush. This is an example of a a. Law b. Belief c. Theory d. Hypothesis

**Answer:**

b

**Explanation:**

Based on illustrations of magnetic field lines, where could an object be placed so it would not experience a magnetic force

**Halfway** between the like poles of two magnets, because the field lines bend away and do not enter this area.

**How does a magnetic field diagram show where the field is strongest?**

**Where is magnetic field the strongest and weakest on a magnet?**

**Which two locations on the magnet would have the greatest attractive forces?**

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As the electric potential near the ground increases during a thunderstorm, a positive charge current can move up pointed objects, such as masts of ships, producing a luminous halo or glow known as ____.

**Answer:**

St. Elmo's Fire - well known to old time sailors

A proud deep-sea fisherman hangs a 69.5-kg fish from an ideal spring having negligible mass. The fish stretches the spring 0.130 m. (a) Find the force constant of the spring.

**Force constant = k = 6811 N/m**

**Given:**

**mass **= m = 69.5 kg

L(initial) = **ideal** spring length = 12 cm= 0.120 m

L(final) = **final** spring length = 13 cm= 0.130 m

**Two forces acting** on the **object** is **k*x** and **mg**

so,

**kx-mg=0**

kx = mg

**k = mg/x**

We know that** x= displacement** =** L(final)- L(initial)**

0.130-0.120=0.10

k= 69.5×9.8/0.10

**k =6811 N/m**

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A 10 kg box initially at rest is pulled with a 50 N horizontal force for 4 m across a level surface. The force of friction acting on the box is a constant 20 N. How much work is done by the 50 N force?

The **work **is **done **by the 50 N force is **200 J.**

Work done = Fd

where;

F is Force applied d is the displacement of the objectWork done = 50 N x 4 m = 200 J

Thus, the **work **is done by the 50 N force is **200 J.**

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What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?

Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They collide, couple, and roll away together with a combined momentum of

The **combined momentum** of the passengers is **5000 kgm/s.**

The** combined momentum** of the passengers is calculated as follows;

P = mv1 + mv2

where;

m is mass of the passengersv1 is velocity of the first passengerv2 is velocity of the second passengerP = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the **combined momentum** of the passengers is **5000 kgm/s.**

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Which type of galaxy is likely to contain only o-spectral type stars?

The answer is Spiral

20. Q: How long will it take for an apple falling from a 29.4m-tall tree to hit the ground?

A: 1.56 s

B: 2.04 s

C: 2.45 s

D: 3.72 s

**Answer:**

2.45s

**Explanation:**

is explanation needed too?

question is down below

The** vertical components **of velocity is ** 10.35 m/s **and the** horizontal component **of velocity is** 38.6 m/s**

We know that **velocity **is a** vector quantity**, a vector often can be resolved into its components. The **vertical **components is **V sinθ** while the **horizontal **component is** vcosθ.**

Hence;

Vertical component = 40 m/s sin 15 degrees =** 10.35 m/s**

Horizontal component = 40 cos 15 degrees = **38.6 m/s**

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The image above shows a crash test dummie's head traveling at -1.005 m/s while striking a headrest from a car traveling 4.524 m/s with a mass of 2005.6 kg. If the crash test dummie's head head bounces off the headrest with a 9.965 m/s and the car continues traveling at 4.487 m/s, calculate the mass of the crash test dummie's head?

Answer:

From the calculation, the **mass **of the **dummies head **is ** 1647.44 Kg**

We know that the **momentum **after **collision **is equal to the **momentum **before **collision**.

Mass of the headrest = 2005.6 kg

Initial velocity of the head rest = 4.524 m/s

Final velocity of the head rest = 4.487 m/s

Mass of the dummy = m

Initial velocity of the dummy = -1.005 m/s

Final velocity of the dummy = 9.965 m/s

Then;

(m * -1.005) + (2005.6 * 4.524 ) = (2005.6 * 4.487) + (m * 9.965)

-1.005m + 9073.33 = 8999.13 + 9.965m

9073.33 - 8999.13 = 9.965m + 1.005m

18072.46 = 10.97m

m = 18072.46/ 10.97

m =** 1647.44 Kg**

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Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coefficient of kinetic friction between the player and the ground is 0.70. His speed at the start of the slide is 8.23 m/s. I a) Calculate his acceleration during the slide. b) How long (in time) does he slide until he stops?

A. The **acceleration** during the slide is** 6.86 m/s²**

B. The** time taken** to slide until he stops is **1.2 s**

F = μN

F = 0.7 × 798.7

**F**** ****=**** ****5****5****9****.****0****9**** ****N**

a = F / m

a = 559.09 / 81.5

**a**** **** ****=**** ****6****.****8****6**** ****m****/****s²**

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

**t = ****1****.****2**** ****s**

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A kettle transfers 6,000j of energy electrically. 1,500j of this is wasted. what is the efficiency of this kettle?

**Answer:75 percent**

**Explanation:so in order tro fin d thge efficiency i used the forumla ,efficency=useful output energy/input energyx100%,in order to use this formula i needed the output,which i found by subtracting the input energy with wasted energy,that gave me the output,and after founding the output,i put that into the formula,**

**output energy=input energy - wasted energy**

**output energy=6000j-1500j**

output energy=4500

put that into the formula

efficiency =output energy/input enrgy x100%

efficiency=4500/6000 multiplied by 100%

efficiency=0.75x100%

efficiency=75%

A certain frictionless simple pendulum having a length l and mass m swings with period t. If both l and m are doubled, what is the new period?.

If l and m both are** doubled** then the **period** becomes √2*T

**what is a simple pendulum?**

It is the one which can be considered to be a point mass suspended from a string or rod of negligible mass.

A pendulum is a weight suspended from a pivot so that it can **swing** freely.

Here,

A certain **frictionless** simple pendulum having a length l and mass m

mass of pendulum = m

length of the pendulum = l

**The period** of simple pendulum is:

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

Where k is the constant.

Now the length and mass are doubled,

m' = 2m

l' = 2l

[tex]T' = 2\pi \sqrt{\frac{2l}{g} }[/tex]

[tex]T' = \sqrt{2}* 2\pi \sqrt{\frac{l}{g} }[/tex]

[tex]T' = \sqrt{2} * T[/tex]

Hence,

If l and m both are** doubled** then the **period** becomes √2*T

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Table 14-10Suppose that a firm in a competitive market faces the following revenues and costs:Quantity Total Revenue Total Cost0 $0 $31 $7 $52 $14 $93 $21 $154 $28 $235 $35 $336 $42 $457 $49 $59Refer to Table 14-10. This firm should continue to produce and sell units as long as the marginal cost of production is less than or equal toa. $3.b. $5.c. $7.d. $9.
companies rely on _____ opportunities to develop marketing strategies that are difficult to replicate and have the potential to make the company a lot of money for a long time.
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TRUE OR FALSESurvey research methods in qualitative research methods are incompatible and should never be combined
Rearrange the words to form correct sentences.1.a/across/and/beauty/has/health/in/interest/of/surge/swept/the/world.2.cause/yet/failure/found/haven't/of/of/security/system/the/the/the/we/whole.3.Alice/everything/for/getting/has/meeting/ready/spent/the/the/week4.cinema/gone/have/last/month/only/out/since/the/they/to/twice/since/last/month.5.already/figures/for/for/has/he/last/poor/reprimanded/sales/the/us/year.
A single isolated, large conducting plate has a charge per unit area on its surface. Because the plate is a conductor, the electric field at its surface is perpendicular to the surface and has magnitude E = /Eo 5, The field from a large, uniformly charged sheet with charge per unit area has magnitude E = /2. why is there a difference? Regard the charge distribution on the conducting plate as two sheets of charge (one on each surface), each with charge per unit area . Find the electric field inside and outside the plate.
according to the book, information profiles about a computer user that are automatically accepted by a web browser and stored on the user's own computer are known as:
You have just taken out a 30-year $100,000 mortgage on your new home. This mortgage is to be repaid in equal end-of-month installments. If the nominal interest rate on the mortgage is 5.43 percent, what is the amount of each monthly payment? O $277.78 O $997.23O $794,40O $563.40 O $642.28
3. the separation of the rotational lines in the p and r branches of 127i 35cl is 0.2284 cm1 . calculate the bondlength
The nurse assistant provided you with the following abnormal vital signs (B/P 189/100, RR 11, Temp 99.6F, and HR 101) on your patient. What should you do next for this patient?a. Ask the nurse assistant to redo the vital signs.b. Do nothing because the values are not too bad.c. Call the physician.d. Redo the vital signs yourself.d
the well-known learning disability label of dyslexia has been stereotyped as mainly seeing letters in reverse order, but in reality, dyslexia is a broader term that includes any learning disorder of group of answer choices
Construct the DAG for the expression ((xy)(xy) (x -y)))((x + y) * (x - y))
there are currently 69 million cars in a certain country, increasing exponentially by 5.1 nnually. how many years will it take for this country to have 89 million cars? round to the nearest year.
according to dolan, what is the downside of the current legislative process?
before designing and implementing a reward system, what organizational factors should the hr manager review?
Michelle Townsend owns stock in National Computers. Based on information in its annual report, National Computers reported after-tax earnings of $9,700,000 and has issued 7,000,000 shares of common stock. The stock is currently selling for $32 a share.a. Calculate the earnings per share for National Computers.b. Calculate the price-earnings (PE) ratio for National Computers.
ANSWER ASAP!! (GIVING BRAINLIEST IF CORRECT!!) Karen measures the width of a garden plot and records that it is 40 meters. Its actual width is 42 meters.What is the percent error in the measurement?A: 2%B: 3%C: 4%D: 5%
For the following function, find the Taylor series centered at x= and then give the first 5 nonzero terms of the Taylor series and the open interval of convergence. f(x)=cos(x)f(x)= n=0[infinity](1) n+1 (2n)!(x) 2nf(x)=++++The open interval of convergence is: (Give your answer in interval notation.) Use series to approximate the definite integral to within the indicated accuracy: 00.7sin(x 3)dx, with an error
describe the tank used to test fire a suspect's gun. how does it work?
Consider the following "ultimatum game." There is a pie with value normalized to one to be allocated between two players. Player 1 starts the game by choosing x[0,1], which specifies an offer where player 1 receives x and player 2 receives 1x. After seeing the offer, player 2 chooses whether to accept or reject. If player 2 accepts, the game ends with payoff u 1=x for player 1 and u 2=1x for player 2 ; if player 2 rejects, both players receive u 1=u 2=0. (a) Find the unique pure-strategy subgame-perfect equilibrium. (b) Find a pure-strategy Nash equilibrium that is not subgame-perfect.