The **population **of sunfish in the small lake decreased from 800 at the beginning to 736 after the first year. **Data** for the second year is missing due to a wildfire, but the population was recorded as 623 during the third year.

To explain further, the recorded** population** numbers indicate a decline in the sunfish population over the observed period. At the beginning, there were 800 sunfish. However, after the first year, the population decreased to 736. This suggests a reduction in the number of sunfish, potentially due to various factors such as predation, disease, or **environmental **changes.

Unfortunately, data for the second year is missing due to the wildfire, so we cannot determine the specific population change during that period. However, in the third year, the biologist recorded a population of 623 sunfish. This further indicates a decline in the sunfish population from the initial count.

It is essential for the marine biologist to continue monitoring the sunfish population to understand the long-term trends and potential factors influencing their numbers. Further **data collection **and analysis will provide valuable **insights** into the dynamics and conservation of the sunfish population in the small lake.

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Please help please i've got a test today please question is provided below please

The **minimum y-value** of this quadratic equation [tex]y=\frac{2}{3} x^2 +\frac{5}{4}x -\frac{1}{3}[/tex] is 353/384 or 0.9193.

In Mathematics and Geometry, the standard form of a **quadratic equation** is represented by the following equation;

ax² + bx + c = 0

Next, we would solve the given **quadratic equation** by using the **completing the square** method;

[tex]y=\frac{2}{3} x^2 +\frac{5}{4}x -\frac{1}{3}[/tex]

In order to **complete the square**, we would re-write the **quadratic equation** and add (half the coefficient of the x-term)² to both sides of the **quadratic equation** as follows:

[tex]y=\frac{2}{3} x^2 +\frac{5}{4}x + (\frac{5}{8})^2 -\frac{1}{3} + (\frac{5}{8})^2\\\\y=\frac{2}{3} (x + \frac{15}{16} )^2-\frac{353}{384} \\\\[/tex]

Therefore, the vertex (h, k) is (15/16, -353/384) and as such, it has a **minimum y-value** of 353/384 or 0.9193.

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which command in R to produce the critical value Za/2 that corresponds to a 98% confidence level? a. qnorm(0.98) b. qnorm(0.02) c. qnorm(0.99) d. qnorm(0.01)

The argument 0.98 in the qnorm function to find the** critical value,** which is 2.33 (rounded to two decimal places).

The correct command in R to produce the **critical value **Za/2 that corresponds to a 98% confidence level is a. qnorm(0.98).

The qnorm function in R is used to calculate the** quantile function** of a normal distribution. The argument of the function is the probability, and it returns the corresponding quantile.

In this case, we are interested in finding the critical value corresponding to a 98% confidence level, which means we need to find the value Za/2 that separates the upper 2% tail of the normal distribution.

Therefore, we use the argument 0.98 in the qnorm function to find the critical value, which is 2.33 (rounded to two decimal places).

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For the following vectors a = [4,8,8], v = [1,1,0] calculate projection of the vector a in the direction of the vector v a = (**) v = [(a) )x, (a )y, (a )z] av VV a = a, +a mi = a - a a = a ū = TS3 0 VU Find magnitude of the vector a. al = [6,6,0) Submit the Answer 2 Question 2 grade: 0

The **magnitude **of **vector **a is 6√2.

To calculate the **projection **of **vector **a onto vector v, we can use the formula:

proj_v(a) = (a · v) / ||v||² × v

where · represents the **dot product **and ||v|| represents the magnitude of vector v.

Given:

a = [4, 8, 8]

v = [1, 1, 0]

First, let's calculate the **dot product **(a · v):

(a · v) = 41 + 81 + 8×0 = 4 + 8 + 0 = 12

Next, let's calculate the **magnitude **of vector v:

||v|| = √(1² + 1² + 0²) = √(2)

Now, we can calculate the **projection **of **vector **a onto v:

= 12 / ((√2)² × [1, 1, 0]

= 12 / 2 x [1, 1, 0]

= 6 [1, 1, 0]

= [6, 6, 0]

The **projection **of **vector **a onto v is [6, 6, 0].

To find the **magnitude **of **vector **a, we can use the formula:

||a|| = √a1² + a2² + a3²

||a|| = √ 6² + 6² + 0²

= √ 36+36

= √72

= 6√2

Thus, The **magnitude **of **vector **a is 6√2.

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the value of the sum of squares due to regression, ssr, can never be larger than the value of the sum of squares total, sst. True or false?

True. The sum of squares due to **regression** (ssr) represents the amount of variation in the dependent variable that is explained by the independent variable(s) in a regression model. On the other hand, the **sum of squares** total (sst) represents the total variation in the dependent variable.

In fact, the **coefficient** of determination (R-squared) in a regression model is defined as the ratio of ssr to sst. It represents the proportion of the** total variation** in the dependent variable that is explained by the independent variable(s) in the model. Therefore, R-squared values range from 0 to 1, where 0 indicates that the model explains none of the variations and 1 indicates that the model explains all of the variations.

Understanding the relationship between** SSR **and sst is important in evaluating the performance of a** regression model **and determining how well it fits the data. If SSR is small relative to sst, it may indicate that the model is not a good fit for the data and that there are other variables or factors that should be included in the model. On the other hand, if ssr is large relative to sst, it suggests that the model is a good fit and that the independent variable(s) have a strong influence on the dependent variable.

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Evaluate double integral double integral D xy^2 dA, D is enclosed by x = 0 and z = square root 1 ? y^2. 6. Evaluate the integral double integral R (x + y)dA by changing to polar coordinates, where R is the region that lies to the left of y-axis between the circles x^2 + y^2 = 1 and x^2 + y^2 = 4. 7. Evaluate the line integral integrate C ydx + zdy + xdz where C: x = square root t, y = t, z = t^2, 1 < = t < = 4. 8(a) Find a function f such that F = gradient f and (b) use part (a) to evaluate integral C F . dr along the curve C where F(x, y) = yzi + xzj + (xy + 2z)k and C is the line segment from (1,0,-2) to (4,6,3).

The double integral of [tex]xy^2[/tex] over the** region** enclosed by x = 0 and z = [tex]sqrt(1 - y^2)[/tex]can be evaluated by converting the integral to polar coordinates. The line integral of[tex]ydx + zdz + xdy[/tex] over the curve C can be evaluated by **parameterizing** the curve and computing the integral

i) To evaluate the double integral of [tex]xy^2[/tex] over the region enclosed by x = 0 and z = sqrt(1 - y^2), we can convert the integral to polar coordinates. We have x = r cos(theta), y = r sin(theta), and z = sqrt(1 - r^2 sin^2(theta)). The region D is **bounded** by the y-axis and the curve x^2 + z^2 = 1. Therefore, the limits of **integration** for r are 0 and 1/sin(theta), and the limits of integration for theta are 0 and pi/2. The integral becomes

int_0^(pi/2) int_0^(1/sin(theta)) r^4 sin(theta)^2 cos(theta) d r d theta.

Evaluating this integral gives the answer (1/15).

ii) To evaluate the integral of (x + y) over the region R that** lies **to the left of the y-axis between the circles [tex]x^2 + y^2 = 1[/tex]and [tex]x^2 + y^2 = 4,[/tex] we can change to **polar coordinates**. We have x = r cos(theta), y = r sin(theta), and the limits of integration for r are 1 and 2, and the limits of integration for theta are -pi/2 and pi/2. The integral becomes

[tex]int_{-pi/2}^{pi/2} int_1^2 (r cos(theta) + r sin(theta)) r d r d theta.[/tex]

Evaluating this integral gives the answer (15/2).

iii) To evaluate the line integral of [tex]ydx + zdz + xdy[/tex] over the curve C, we can parameterize the** curve** using t as the parameter. We have x = sqrt(t), y = t, and z [tex]= t^2[/tex]. Therefore, dx/dt = 1/(2 sqrt(t)), dy/dt = 1, and dz/dt = 2t. The integral becomes

[tex]int_1^4 (t dt/(2 sqrt(t)) + t^2 dt + sqrt(t) (2t dt)).[/tex]

Evaluating this integral gives the answer (207/4).

iv) To find the function f such that F = grad f, we can integrate the **components** of F. We have f(x, y, z) = [tex]xy z + x^2 z/2 + y^2 z/2 + z^2/2[/tex]+ C, where C is a constant. To evaluate the line integral of [tex]F.dr[/tex] along the curve C, we can plug in the **endpoints **of the curve into f and take the difference. The integral becomes

f(4, 6, 3) - f(1, 0, -2) = 180.

Therefore, the answer is 180.

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. prove that if v is a vector space having dimension n, then a system of vectors v1, v2, . . . , vn in v is linearly independent if and only if it spans v .

A system of **vectors **v1, v2, . . . , vn in a vector space v of dimension n is **linearly independent **if and only if it spans v.

Let's first assume that the system of vectors v1, v2, . . . , vn in v is **linearly independent**. This means that none of the **vectors **can be written as a linear combination of the others. Since there are n vectors and v has dimension n, it follows that the system is a basis for v. Therefore, every vector in v can be written as a **unique linear combination **of the vectors in the system, which means that the system spans v.

Conversely, let's assume that the system of vectors v1, v2, . . . , vn in v spans v. This means that every vector in v can be written as a linear combination of the vectors in the system. Suppose that the system is linearly dependent. This means that there exists at least one vector in the system that can be written as a linear combination of the others. Without loss of generality, let's assume that vn can be written as a linear combination of v1, v2, . . . , vn-1. Since v1, v2, . . . , vn-1 span v, it follows that vn can also be written as a linear combination of these vectors. This contradicts the assumption that vn cannot be written as a linear combination of the others. Therefore, the system must be linearly independent.

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Help, god help. I need to know ASAP in 9 days before april 1 HELP. One of the bases of a trapezoid has length $10$, and the height of the trapezoid is $4$. If the area of the trapezoid is $36$, then how long is the other base of the trapezoid?

The other **base **of the **trapezoid **is 8 units long.

Let's denote the other base of the trapezoid as 'x'. The formula for calculating the area of a **trapezoid **is given by A = (1/2)(b1 + b2)h, where b1 and b2 represent the lengths of the bases and 'h' represents the height. We are given that the **length **of one base (b1) is 10 units, the height (h) is 4 units, and the area (A) is 36 square units.

Using the formula for the area, we can plug in the given values: 36 = (1/2)(10 + x)(4). Simplifying the **equation**, we get 36 = (5 + 0.5x)(4). Further simplification yields 36 = 20 + 2x. By subtracting 20 from both sides of the equation, we obtain 16 = 2x. Dividing both **sides **by 2 gives us x = 8.

Therefore, the other base of the trapezoid is 8 units long.

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During a record setting rainfall 0. 057 inch of rain fell every minute for 35 minutes. How much rain fell in 10 minutes?

During a **record-setting** rainfall of 0.057 inches of rain falling every minute for 35 minutes, we need to find out how much rain fell in 10 minutes. To get the answer, we need to use the **proportionality **concept.

Proportionality concept is a rule that describes how two different values are related to each other. It states that if a/b = c/d then ad = bc.This proportionality **concept **can be applied to the rainfall as follows:0.057 inches of rain fall every minuteTherefore, we can write this as:0.057/1 = x/10 (rainfall for 10 minutes)Where x represents the amount of rainfall in 10 minutes.Now, we need to **solve** for x. We can do this by **cross-multiplying **the above equation.0.057 × 10 = x x = 0.57Therefore, the amount of rainfall that fell in 10 minutes is 0.57 inches.

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Debora deposits $5000 into a savings account. The bank promises to provide an annual interest rate of 5%, compounded yearly. Assuming that Debora keeps the money in her bank account and does not withdraw any funds, calculate the value of her investment after 10 years

After 10 years, **Debora's **investment of $5000 in the savings account with a 5% annual** interest rate**, compounded yearly, will grow to approximately $6,633.16.

To calculate the value of Debora's investment after 10 years, we can use the formula for **compound interest**:

[tex]A = P(1 + r/n)^(nt)[/tex]

Where:

A is the **final amount** (the value of the investment after the given time period)

P is the principal amount (the initial deposit)

r is the annual interest rate (expressed as a **decimal**)

n is the number of times interest is compounded per year

t is the number of years

In this case, Debora deposits $5000 into the savings account with an annual interest rate of 5%, compounded yearly. Plugging in the values into the formula:

[tex]A = 5000(1 + 0.05/1)^(1*10)[/tex]

**Simplifying **the calculation:

[tex]A = 5000(1.05)^10[/tex]

Using a calculator or computing the value iteratively, we find:

A ≈ 5000 * 1.628895

A ≈ 6,633.16

Therefore, after 10 years, Debora's investment of $5000 in the savings account will grow to approximately $6,633.16. This means that the investment will accumulate approximately $1,633.16 in interest over the 10-year period, given the 5% annual interest rate compounded yearly.

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Find the number of paths of length 2 in the kingdom in terms of n.

Without further information about the "kingdom" or the structure of its paths, it is not possible to determine the number of paths of length 2 in terms of n.

Can you please provide more information or context about the problem, such as a definition of the "kingdom" or a description of the possible paths?

Consider the series [infinity]

∑ n/(n+1)!

N=1 A. Find the partial sums s1, s2, s3, and s4. Do you recognize the denominators? Use the pattern to guess a formula for sn. B. Use mathematical indication to prove your guess. C. Show that the given infinite series is convergent and find its sum.

**Answer:**

A. To find the partial sums of the series ∑n/(n+1)! from n = 1 to n = 4, we plug in the values of n and add them up:

s1 = 1/2! = 1/2

s2 = 1/2! + 2/3! = 1/2 + 2/6 = 2/3

s3 = 1/2! + 2/3! + 3/4! = 1/2 + 2/6 + 3/24 = 11/12

s4 = 1/2! + 2/3! + 3/4! + 4/5! = 1/2 + 2/6 + 3/24 + 4/120 = 23/30

The denominators of the terms in the partial sums are the factorials, specifically (n+1)!.

We notice that the terms in the numerator of the series are consecutive integers starting from 1. Therefore, we can write the nth term as n/(n+1)!, which can be expressed as (n+1)/(n+1)!, or simply 1/n! - 1/(n+1)!. Thus, the series can be written as:

∑n/(n+1)! = ∑[1/n! - 1/(n+1)!]

Using this expression, we can write the partial sum sn as:

sn = 1/1! - 1/(2!) + 1/2! - 1/(3!) + 1/3! - ... + 1/n! - 1/((n+1)!)

B. To prove that the formula for sn is correct, we can use mathematical induction.

Base case: n = 1

s1 = 1/1! - 1/(2!) = 1/2, which matches the formula for s1.

Inductive hypothesis: Assume that the formula for sn is correct for some value k, that is,

sk = 1/1! - 1/(2!) + 1/2! - 1/(3!) + 1/3! - ... + 1/k! - 1/((k+1)!).

Inductive step: We need to show that the formula is also correct for n = k+1, that is,

sk+1 = 1/1! - 1/(2!) + 1/2! - 1/(3!) + 1/3! - ... + 1/k! - 1/((k+1)!) + 1/((k+1)!) - 1/((k+2)!).

Simplifying this expression, we get:

sk+1 = sk + 1/((k+1)!) - 1/((k+2)!)

Using the inductive hypothesis, we substitute the formula for sk and simplify:

sk+1 = 1/1! - 1/(2!) + 1/2! - 1/(3!) + 1/3! - ... + 1/k! - 1/((k+1)!) + 1/((k+1)!) - 1/((k+2)!)

= 1/1! - 1/(2!) + 1/2! - 1/(3!) + 1/3! - ... + 1/k! + 1/((k+1)!) - 1/((k+2)!)

= ∑[1/n! - 1/(n

By examining the first few terms, we can see that the denominators are factorial expressions with a shift of 1, i.e., **(n+1)! = (n+1)n!.** Using this pattern, we can guess that the nth partial sum of the series is given by **sn = 1 - 1/(n+1).**

The given series is a sum of terms of the form** n/(n+1)!** which have a pattern in their denominators.

To prove this guess, we can use **mathematical induction**. First, we note that s1 = 1 - 1/2 = 1/2. Now, assuming that sn = 1 - 1/(n+1), we can find sn+1 as follows:

sn+1 = sn + (n+1)/(n+2)!

= 1 - 1/(n+1) + (n+1)/(n+2)!

= 1 - 1/(n+2).

This confirms our guess that sn = 1 - 1/(n+1).

To show that the series is **convergent,** we can use the ratio test. The ratio of consecutive terms is given by (n+1)/(n+2), which approaches 1 as n approaches infinity. Since the limit of the ratio is less than 1, the series converges. To find its sum, we can use the formula for a convergent geometric series:

∑ n/(n+1)! = lim n→∞ sn = lim n→∞ (1 - 1/(n+1)) = 1.

Therefore, the sum of the given** infinite series is 1.**

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The water level (In feet) In Boston Harbor during a certain 24 hour period is approximated by the formula H = 4 8 sin [pi/6(t - 10)] + 7.6, 0 LE t LE 24 where t = 0 corresponds to 12 AM What it the average water level in Boston Harbor over the 24 hour period on that day? At what times of the day did the water level in Boston Harbor equal the average water level? (use Mean value Theorem for integrates) Newton's Law of cooling, A bottle of white wine at room temperature (70Degree F) is placed in a refrigerator at 3 P.M. Its temperature after t hours is changing at the rate of -18e^-65l eF/hr. By how many degrees will the temperature of the wine have dropped by 6 P.M? What will be the temperature of the wine be at 6P.M? sketch graphs of the functions n(t) = 18e ^65t eF/hr, and its antiderivative N(t). Where on the graphs of n(t) and N(t) can the solution to part (a) be found? Point them out. And why does it make sense that N(t) has a horizontal asymptote where it does?

(a) Average water level = 7.6 feet

(b) The water level in Boston Harbor equals the average water level at

t = 10, 14, 18, and 22.

(c) **Temperature** at 6 P.M. = 70 - 9.02 = 60.98 degrees Fahrenheit.

(d) It makes sense that N(t) has a horizontal asymptote at y = 0 because as t becomes

**What is integration?**

Integration is a mathematical **operation** that is the reverse of differentiation. Integration involves finding an **antiderivative** or indefinite integral of a function.

a) To find the average water level in Boston Harbor over the 24 hour period, we need to calculate the integral of the function H(t) over the interval [0,24] and divide by the length of the interval. Using the Mean Value Theorem for Integrals, we have:

Average water level = (1/24) * ∫[0,24] H(t) dt

= (1/24) * [ -8cos(pi/6(t-10)) + (15.2t - 384sin(pi/6(t-10))) ] evaluated from 0 to 24

= 7.6 feet

b) To find the times of the day when the water level in Boston Harbor equals the average water level, we need to solve the equation H(t) = 7.6. Using the given formula for H(t), we have:

48sin[pi/6(t-10)] + 7.6 = 7.6

48sin[pi/6(t-10)] = 0

sin[pi/6(t-10)] = 0

t-10 = (2n)π/6 or t-10 = (2n+1)π/6, where n is an integer.

Solving for t, we get:

t = 10 + (2n)4 or t = 10 + (2n+1)2.5, where n is an integer.

Therefore, the water level in Boston Harbor equals the average water level at t = 10, 14, 18, and 22.

c) Newton's Law of Cooling states that the rate of change of the temperature of an object is proportional to the difference between its temperature and the temperature of its surroundings. In this case, the temperature of the wine is changing at a rate of [tex]-18e^{(-65t)}[/tex] degrees Fahrenheit per hour. To find how much the temperature drops between 3 P.M. and 6 P.M., we need to calculate the integral of the rate of change of temperature over the interval [0,3] and multiply by -1 to get a positive value. Using the formula for the rate of change of temperature, we have:

ΔT = -∫[0,3] - [tex]18e^{(65t)}[/tex] dt

= [-18/(-65) [tex]e^{(-65t)}[/tex]] evaluated from 0 to 3

≈ 9.02 degrees Fahrenheit

Therefore, the temperature of the wine drops by approximately 9.02 degrees Fahrenheit between 3 P.M. and 6 P.M. To find the temperature of the wine at 6 P.M., we need to subtract the temperature drop from the initial temperature of 70 degrees Fahrenheit:

Temperature at 6 P.M. = 70 - 9.02 = 60.98 degrees Fahrenheit.

d) The graph of n(t) = [tex]18e^{(65t)}[/tex] is an increasing exponential function with a horizontal asymptote at y = 0. The graph of its antiderivative N(t) = [tex](18/65)e^{(65t)}[/tex] is an increasing exponential function with a horizontal asymptote at y = 0 as well.

The solution to part (a) can be found on the graph of N(t) at y = 7.6, which represents the average water level in Boston Harbor over the 24 hour period.

The solution to part (b) can be found on the graph of H(t), which intersects with the horizontal line y = 7.6 at t = 10, 14, 18, and 22. It makes sense that N(t) has a horizontal asymptote at y = 0 because as t becomes

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11.23. consider the equivalence relation from exercise 11.3. find [x2 3x 1]; give this in description notation, without any direct reference to r.

The equivalence class [x2 3x 1] without directly referencing the **equivalence relation** r.

To find the equivalence class of [x2 3x 1] under the equivalence relation from exercise 11.3, we need to determine all the elements that are related to this tuple.

Recall that the equivalence relation in question is defined as follows: two tuples (a1, a2, a3) and (b1, b2, b3) are related if and only if a1 + a2 + a3 = b1 + b2 + b3.

So, we need to find all **tuples **(y1, y2, y3) such that y1 + y2 + y3 = x2 + 3x + 1.

One way to do this is to fix one of the variables and solve for the others. For example, let's fix y1 = 0. Then we have y2 + y3 = x2 + 3x + 1.

This is a linear **equation **in two **variables**, so we can solve for one variable in terms of the other. Let's solve for y2:

y2 = x2 + 3x + 1 - y3

Now, we can choose any value for y3, and y2 will be determined accordingly. So, the set of all tuples (y1, y2, y3) that satisfy the equivalence relation and have y1 = 0 is given by:

{(0, x2 + 3x + 1 - y3, y3) | y3 ∈ Z}

Similarly, we can fix y2 or y3 and solve for the other two variables to obtain the sets of tuples that satisfy the equivalence relation and have those variables fixed.

In general, the set of all tuples (y1, y2, y3) that satisfy the equivalence relation and have y1 = a, y2 = b, or y3 = c is given by:

{(a, b + x2 + 3x + 1 - a - c, c) | a, b, c ∈ Z}

This describes the equivalence class [x2 3x 1] without directly referencing the equivalence relation r.

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Find the exact value of tan A in simplest radical form.

16√93/93 is the equivalent** value of tan A **in its simplest form

The given diagram is a **right angles** triangle.

We need to determine the **measure of tan A** from the diagram. Using the trigonometry identity:

tan A = opposite/adjacent

adjacent = √93

opposite = 14

**Substitute** to have:

tan A = 16/√93

tan A = 16√93/93

Hence the m**easure of tan A** as a fraction in its simplest form is 16√93/93

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Every student at a music college learns the

piano, the guitar, or both the piano and the

guitar.

of the students who learn the piano also

learn the guitar.

5 times as many students learn the guitar

as learn the piano.

x students learn both the piano and the

guitar.

Find an expression, in terms of x, for the

total number of students at the college.

The required **expression** for the total number of students at the college is 11x.

A Venn diagram is a diagram that uses overlapping circles or other patterns to depict the logical relationships between two or more groups of things.

According to the given **Venn** **diagram**,

1/2 of the students who learn the piano also learn the guitar (both piano and guitar) is x

Therefore, the expression for students who learn the **piano** is 2x

and the expression for students who learn the **guitar** is 2x × 5 = 10x.

The **expression** for the total number of students at the college can be written as:

2x + 10x - x = 11x

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The complete question is attached below in the image:

3. determine whether the given functions form a fundamental solution set to an equation x’(t) = ax. if they do, find a fundamental matrix for the system and give a general solution.

Here c1 and c2 are constants determined by the initial conditions. To determine whether the given **functions** form a fundamental solution set to the **equation** x’(t) = ax, we need to check if they are linearly independent and if they satisfy the equation. Let the given functions be f1(t) and f2(t).

First, we need to check if they satisfy the equation x’(t) = ax. We have:

f1’(t) = a f1(t) and f2’(t) = a f2(t)

This shows that both f1(t) and f2(t) satisfy the equation.

Next, we need to check if they are **linearly** independent. To do this, we can form a matrix with the two functions as its columns and take its determinant.

| f1(t) f2(t) |

| f1’(t) f2’(t) |

Expanding the determinant, we get:

f1(t) f2’(t) - f2(t) f1’(t) = W(t)

where W(t) is the Wronskian of f1(t) and f2(t). If W(t) is not identically zero, then f1(t) and f2(t) are linearly independent and form a fundamental solution set.

Therefore, if W(t) is not identically zero, we can find a **fundamental matrix** for the system as follows:

| f1(t) f2(t) |

| f1’(t) f2’(t) |

And the general solution can be written as:

x(t) = c1 f1(t) + c2 f2(t)

where c1 and c2 are constants determined by the initial conditions.

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x and y each take on values 0 and 1 only and are independent. their marginal probability distributions are:

f(x) =1/3, if X = 0 and f(x) = 2/3 if X = 1 f(y) =1/4, if Y = 0 and f(y) = 3/4 if Y = 1 Determine corresponding joint probability distribution.

The corresponding joint **probability distribution **is:

X\Y 0 1

0 1/12 1/4

1 1/6 1/2

Since X and Y are independent, the joint probability distribution is **simply **the product of their **marginal** probability distributions:

f(x,y) = f(x) × f(y)

Therefore, we have:

f(0,0) = f(0) ×f(0) = (1/3) × (1/4) = 1/12

f(0,1) = f(0) × f(1) = (1/3) × (3/4) = 1/4

f(1,0) = f(1) × f(0) = (2/3) × (1/4) = 1/6

f(1,1) = f(1) ×f(1) = (2/3) × (3/4) = 1/2

**Therefore**, the corresponding joint probability distribution is:

X\Y 0 1

0 1/12 1/4

1 1/6 1/2

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compute (manually, using the vector/matrix equation) the dft of the time sequence: x[k]={1, 1, 1, 1}. verify the answer using the matlab. also, find the dc value of the obtained sequence x[n].

The **DC value **of the obtained **sequence** x[n] is simply the first element, x[0] = 4.

To compute the DFT of the time sequence x[k] = {1, 1, 1, 1}, we use the following formula:

X[n] = ∑[k=0 to N-1] x[k] * exp(-j * 2π * k * n / N)

where N is the **length **of the sequence, x[k] is the value of the sequence at index k, X[n] is the value of the DFT at index n, and j is the **imaginary unit**.

For this sequence, N = 4, so we have:

X[0] = 1 * exp(-j * 2π * 0 * 0 / 4) + 1 * exp(-j * 2π * 1 * 0 / 4) + 1 * exp(-j * 2π * 2 * 0 / 4) + 1 * exp(-j * 2π * 3 * 0 / 4)

= 4

X[1] = 1 * exp(-j * 2π * 0 * 1 / 4) + 1 * exp(-j * 2π * 1 * 1 / 4) + 1 * exp(-j * 2π * 2 * 1 / 4) + 1 * exp(-j * 2π * 3 * 1 / 4)

= 0

X[2] = 1 * exp(-j * 2π * 0 * 2 / 4) + 1 * exp(-j * 2π * 1 * 2 / 4) + 1 * exp(-j * 2π * 2 * 2 / 4) + 1 * exp(-j * 2π * 3 * 2 / 4)

= 0

X[3] = 1 * exp(-j * 2π * 0 * 3 / 4) + 1 * exp(-j * 2π * 1 * 3 / 4) + 1 * exp(-j * 2π * 2 * 3 / 4) + 1 * exp(-j * 2π * 3 * 3 / 4)

= 0

Therefore, the **DFT **of the sequence x[k] is X[n] = {4, 0, 0, 0}.

To verify this result using MATLAB, we can use the built-in function fft:x = [1 1 1 1];

X = fft(x)This gives us X = [4 0 0 0], which matches our computed result.

The **DC value **of the obtained **sequence **x[n] is simply the first **element**, x[0] = 4.

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Let X and Y be independent random variables, uniformly distributed in the interval [0,1]. Find the CDF and the PDF of X - Y). (3) Find the PDF of Z = X + Y, when X and Y are independent Exponential random variables with common narameter 2

The** CDF** of Z is:

**F_Z(z) = { 0 for z < 0**

{ 1/2 - z/2 for 0 ≤ z < 1

{ 1 for z ≥ 1

(a) Let Z = X - Y. We will find the **CDF** and PDF of Z.

The **CDF **of Z is given by:

**F_Z(z) = P(Z <= z)**

= P(X - Y <= z)

= ∫∫[x-y <= z] f_X(x) f_Y(y) dx dy (by the definition of joint PDF)

= ∫∫[y <= x-z] f_X(x) f_Y(y) dx dy (since x - y <= z is equivalent to y <= x - z)

= ∫_0^1 ∫_y+z^1 f_X(x) f_Y(y) dx dy (using the limits of y and x)

= ∫_0^1 (1-y-z) dy (since X and Y are uniformly distributed over [0,1], their PDF is constant at 1)

**= 1/2 - z/2**

Hence, the **CDF **of Z is:

F_Z(z) = { 0 for z < 0

{ 1/2 - z/2 for 0 ≤ z < 1

{ 1 for z ≥ 1

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consider the following curve. y = 1 x 5 ex find y ′(x). y ′(x) = find an equation of the tangent line to the given curve at the point 0, 1 6 . y =

**Equation **of the tangent at (0, 1/7) is y = (5/36)x + 1/7.

To find an equation of the **tangent **line to the curve y = (1 + x)/(6 + [tex]e^{x}[/tex] ) at the point (0, 1/7), we need to find the slope of the tangent line at that point and then use point-slope form to write the equation of the line.

To find the slope of the tangent line, we need to take the derivative of y with respect to x, and evaluate it at x = 0:

y' = [(6 + [tex]e^{x}[/tex])(1) - (1 + x)( [tex]e^{x}[/tex])]/[tex](6+e^{x} )^{2}[/tex]

At x = 0, we have:

y' = [(6 + [tex]e^{0}[/tex])(1) - (1 + 0)([tex]e^{0}[/tex])]/[tex](6+e^{0} )^{2}[/tex] = 5/36

So, the **slope **of the tangent line at (0, 1/7) is 5/36.

Now, we can use point-slope form to write the equation of the tangent line:

y - [tex]y_{1}[/tex] = m(x - [tex]x_{1}[/tex])

where m is the slope we just found, and ([tex]x_{1}[/tex], [tex]y_{1}[/tex]) is the point we're given, (0, 1/7).

**Substituting **the values, we get:

y - 1/7 = (5/36)(x - 0)

Simplifying, we get:

y = (5/36)x + 1/7

Therefore, the equation of the tangent line to the curve y = (1 + x)/(6 + [tex]e^{x}[/tex]) at the point (0, 1/7) is y = (5/36)x + 1/7.

Correct Question :

Find An Equation Of The Tangent Line To The Given Curve At The Specified Point. y =(1+x)/(6+[tex]e^{x}[/tex]) , (0, 1 /7 ).

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Question 1 Estimate the annual energy consumption (in kilowatt-hour) of a typical house in Arizona _____. Question 2 Solar panels generate an average of about 200 Watt/m2. Estimate the area (in meter2) needed to provide this annual energy usage. ____

The average annual **energy** consumption for a typical house in Arizona is about 12,000 kilowatt-hours.

About 6.28 square meters of solar panels would be needed to provide the annual energy usage for a typical house in Arizona.

To estimate the annual energy consumption of a typical house in Arizona, let's first consider that the average U.S. household consumes around 10,972 kWh per year. **Arizona** is hotter than the national average, so energy **consumption** may be slightly higher due to the increased use of air conditioning. However, as a rough estimate, we can assume the annual energy consumption of a typical house in Arizona is around 11,000 kWh.

To estimate the **area** needed for solar panels to provide this annual energy usage, we first need to determine how much energy the solar panels can generate annually. With an average generation of 200 W/m², we can convert this to kWh per year as follows:

200 W/m² * 24 hours/day * 365 days/year = 1,752,000 Wh/m²/year = 1,752 kWh/m²/year

Now, we can find the area needed to generate 11,000 kWh annually by dividing the annual energy consumption by the energy generation per square meter:

11,000 kWh / 1,752 kWh/m² = 6.28 m²

So, approximately 6.28 square meters of solar panels would be needed to provide the annual energy usage for a typical house in Arizona.

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fill in the blank. anthony placed an advertisement for a new assistant on november 1. he hired marquis on december 1. his _______ was 30 days.

Anthony's "**hiring process**" or "**recruitment period**" was 30 days.

The blank can be filled with "hiring process" or "recruitment period" to indicate the duration between placing the advertisement for a new assistant on November 1 and hiring Marquis on December 1. This **period **represents the time it took Anthony to evaluate applicants, conduct interviews, and make the decision to hire Marquis.

The **hiring process** typically involves several steps, such as advertising the job opening, reviewing applications, conducting interviews, and finalizing the selection. The duration of this process can vary depending on various factors, including the number of applicants, the complexity of the position, and the efficiency of the hiring process.

In this case, the hiring process took 30 days, indicating the** length **of time it took for Anthony to complete the necessary steps and choose Marquis as the new assistant. This **duration** provides insight into the timeframe Anthony needed to assess candidates and make a hiring decision.

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what are the dimensions of a rectangle with the largest area that can be drawn inside a circle with radius 5

The dimensions of a **rectangle** with the largest area that can be drawn inside a circle with a radius of 5 are L = 5.77 and W = 8.16.

The **diameter** of the circle is twice the radius, so it is 2 × 5 = 10.

Let's assume that the length of the rectangle is L and the width is W.

Since the **diagonal** of the rectangle is equal to 10, we can use the **Pythagorean **theorem to express the relationship between the length, width, and diagonal

L² + W² = 10²

L² + W² = 100

To find the dimensions that maximize the area of the rectangle, we need to **maximize **the product L × W. One way to do this is to find the maximum value for L² × W².

W² = 100 - L²

Substituting this into the area formula, A = L × W, we have

A = L × (100 - L²)

To find the maximum area, we can take the **derivative **of A concerning L, set it equal to zero, and solve for L

dA/dL = 100 - 3L² = 0

3L² = 100

L² = 100/3

L = √(100/3)

Substituting this value of L back into the equation for W^2, we have

W² = 100 - (100/3)

W² = 200/3

W = √(200/3)

Therefore, the **dimensions **of the rectangle with the largest area that can be inscribed inside a circle with a radius of 5 are approximately L = 5.77 and W = 8.16.

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use part 1 of the fundamental theorem of calculus to find the derivative of the function g(x) = ∫x-1 1 / t^3 1 dt

By using the fundamental theorem of calculus, the **derivative** of the given function g(x) = ∫[tex]x^{-1} (1 / t^3)[/tex] dt is obtained as 1 / [tex]x^3[/tex].

To find the derivative of the function g(x) = ∫x^(-1) (1 / t^3) dt using the **Fundamental Theorem of Calculus**, we will apply Part 1 of the theorem.

Part 1 states that if a function g(x) is defined as the integral of another function F(t) with respect to t, where the **upper limit of integration** is x, then the derivative of g(x) can be found by evaluating F(x) and taking its derivative.

In this case, we need to determine the function F(t) that, when differentiated, will yield the **integrand** (1 / [tex]t^3[/tex]). Integrating (1 / [tex]t^3[/tex]) with respect to t, we obtain -1 / ([tex]2t^2[/tex]).

Therefore, F(t) = -1 / ([tex]2t^2[/tex])

Next, we can find the derivative of g(x) by evaluating F(x) and taking its derivative.

The derivative of F(x) is obtained by applying the **power rule** for **differentiation**:

g'(x) = d/dx [F(x)]

= d/dx [-1 / ([tex]2x^2[/tex])]

= (1 / 2)[tex](2x^2)^{(-1-1)}[/tex] × 2

= (1 / 2)(2 / [tex]x^3[/tex])

= 1 / ([tex]x^3[/tex]).

Thus, the derivative of g(x) is given by 1 / ([tex]x^3[/tex]). This derivative represents the rate of change of the integral with respect to x.

Therefore, for any given value of x, the derivative tells us how the integral value changes as x varies.

In conclusion, the derivative of the function g(x) = ∫[tex]x^{-1} (1 / t^3)[/tex] dt is 1 / ([tex]x^3[/tex]), which signifies the rate of change of the integral with respect to x.

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solve the equation by completing the square. 4x2 − x = 0 x = (smaller value) x = (larger value)

To solve the given **equation**, we need to complete the square. First, we can factor out 4 from the equation to get 4(x^2 - 1/4x) = 0. To complete the square, we need to add (1/2)^2 = 1/16 to both sides of the equation. This gives us 4(x^2 - 1/4x + 1/16) = 1. We can simplify this to (2x - 1/2)^2 = 1/4.

Taking the square root of both sides gives us 2x - 1/2 = ± 1/2. Solving for x, we get x = 1/4 or x = 0. Therefore, the smaller value of x is 0 and the larger **value** of x is 1/4. Completing the square helps us find the values of x that satisfy the equation by manipulating it into a form that can be more easily solved.

To solve the equation 4x² - x = 0 by completing the square, follow these steps:

1. Divide the equation by the coefficient of x² (4): x² - (1/4)x = 0

2. Take half of the coefficient of x and **square** it: (1/8)² = 1/64

3. Add and subtract the value obtained in step 2: x² - (1/4)x + 1/64 = 1/64

4. Rewrite the left side as a perfect square: (x - 1/8)² = 1/64

5. Take the square root of both sides: x - 1/8 = ±√(1/64)

6. Solve for x to find the two values: x = 1/8 ±√(1/64)

The smaller value: x = 1/8 - √(1/64)

The larger value: x = 1/8 + √(1/64)

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(2 points) the lynx population on a small island is observed to be given by the function P(t) = 121t - 0.4t^4 + 1000. where t is the time (in months) since observations of the island began. The number of lyn x on the island when first observed is___lynx.

The **initial population** of lynx on the island is 1000 lynx.

To find the initial population of lynx on the island, we need to look at the equation for P(t) when t = 0.

This is because t represents the **time **since observations of the island began, so when t = 0, this is the starting point of the observations.

Therefore, we can substitute t = 0 into the **equation **for P(t):

P(0) = 121(0) - 0.4(0)⁴ + 1000

P(0) = 0 - 0 + 1000

P(0) = 1000

So the initial population of lynx on the island is 1000 lynx.

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if you rolled two dice, what is the probability that you would roll a sum of 5?

The required **probability **of rolling a sum of 5 with two dice is 1/9.

Given that two dice are rolled and find the **probability **of a sum of 5.

To find the **probability **of rolling a sum of 5 with two dice, write the sample space and then determine the number of **favourable **outcomes that is the **outcomes **where the sum is 5 and the total **number **of possible outcomes.

The formula to find out the **probability **of any event is

P(event) = (number of **favourable **outcomes) / total number of possible outcomes.

The **sample space** of the event of rolling two dice is

S = { (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

The total possible **outcomes **is 36.

The **favourable **outcomes that is the outcomes where the sum is 5 is

(1, 4), (2, 3), (3, 2), (4, 1).

The number of **favourable **outcomes are 4.

By using the data and formula, the probability of rolling a sum of 5 is,

P(rolling a sum of 5) = (number of **favourable **outcomes) / total number of possible **outcomes**.

P(rolling a **sum **of 5) = 4/ 36

On dividing both numerator and **denominator **by 4 gives,

P(**rolling **a sum of 5) = 1/9.

Hence, the required **probability **of rolling a sum of 5 with two dice is 1/9.

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What is the maximum value of the absolute value parent function on

-10≤x≤ 10?

A. -1

B. 10

C. 0

D. -10

The maximum value of the absolute value **parent function** on the interval -10 ≤ x ≤ 10 is 10. B.

The absolute value parent function is defined as f(x) = |x| the absolute value of x is the **distance **between x and zero on the number line.

On the given interval of -10 ≤ x ≤ 10 can see that the maximum value of f(x) occurs at the endpoints of the interval x = -10 or x = 10.

The absolute value of x is 10, so f(x) = |x| = 10.

Thus, the maximum value of the absolute value parent function on the interval -10 ≤ x ≤ 10 is 10.

This means that the graph of the function will have a "**peak**" at x = -10 and x = 10 the function takes on its maximum value.

The minimum value of the absolute value parent function on this interval is 0 occurs at x = 0.

This is because the absolute value of any **non-zero** number is positive so f(x) can never be negative.

The maximum value of the absolute value parent function on the **interval **-10 ≤ x ≤ 10 is 10.

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Andre tried to solve the equation 14(x+12)=2. andre tried to solve the equation 14(x+12)=2. andre tried to solve the equation 14(x+12)=2. andre tried to solve the equation 14(x+12)=2.

In order to solve the equation 14(x + 12) = 2, we need to follow the order of operations which is also known as PEMDAS which stands for** Parentheses**, Exponents, **Multiplication** and Division, and Addition and Subtraction. Let's solve the equation below step by step;

First of all, let us get rid of the parenthesis by multiplying 14 by each of the terms inside of the parenthesis;14(x + 12) = 2 Distribute 14 to both x and 12.14x + 168 = 2 Combine **like** terms.14x = -166 Now, we need to isolate the variable (x) by dividing both sides of the equation by 14, since 14 is being multiplied by x.14x/14 = -166/14 x = -83/7Therefore, the solution for the **equation** 14(x + 12) = 2 is x = -83/7 which is equal to -11.86 (rounded to the nearest two decimal places).The solution can be confirmed by substituting -83/7 for x in the original equation and **ensuring **that the equation is true.

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The Bem Sex Role Inventory (BSRI) provides independent assessments of masculinity and femininity in terms of the respondent's self-reported possession of socially desirable, stereotypically masculine and feminine personality characteristics Alison Konrad and Claudia Harris sought to compare northern U.S. and southern U.S. women on their judgments of the desirability of 40 masculine, feminine, or androgynous traits. Suppose that the following are the scores from a hypothetical sample of northern U.S. women for the attribute Sensitive 3 1 1 23 Calculate the mean, degrees of freedom, variance, and standard deviation for this sample

The **mean** for the sample is calculated by adding up all the scores and dividing by the number of scores in the sample. In this case, the sum of the scores is 28 (3+1+1+23) and there are 4 scores, so the mean is 7 (28/4).

The **degrees **of freedom for this sample is 3, which is the number of scores minus 1 (4-1).

The variance is calculated by taking the difference between each score and the mean, squaring those differences, adding up all the squared differences, and dividing by the degrees of freedom. In this case, the differences from the mean are -4, -6, -6, and 16. Squaring these differences gives 16, 36, 36, and 256. Adding up these squared differences gives 344. Dividing by the degrees of freedom (3) gives a** variance** of 114.67.

The standard deviation is the **square root** of the variance. In this case, the standard deviation is approximately 10.71.

the mean score for the northern U.S. women on the attribute Sensitive is 7, with a variance of 114.67 and a standard deviation of approximately 10.71. These statistics provide information about the distribution of scores for this sample.

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Therefore, the mean is 7, the degrees of freedom is 3, the variance is 187.33, and the **standard deviation** is 13.68 for this sample of northern U.S. women on the attribute Sensitive.

To calculate the **mean**, we add up all the scores and divide by the number of scores:

Mean = (3 + 1 + 1 + 23) / 4 = 7

To calculate the **degrees of freedom** (df), we subtract 1 from the number of scores:

df = 4 - 1 = 3

To calculate the **variance**, we first find the difference between each score and the mean, square each difference, and add up all the squared differences. We then divide the sum of squared differences by the degrees of freedom:

Variance = ((3-7)² + (1-7)² + (1-7)² + (23-7)²) / 3

= 187.33

To calculate the standard deviation, we take the square root of the variance:

Standard deviation = √(187.33)

= 13.68

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Submit your 150-word letter of application that follows the proper format and references the hiring manager and job title as well as your name and qualifications. ( if someone can answer this imma cri)
Tito builds a model of the solar system. In his model, the diameter of the sphere representing Jupiter is 7 inches. What is the circumference of a cross section through the center of the model of Jupiter? Use 3.14 for
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